1.
Factorial Notation:
Let n be a positive integer. Then, factorial
n, denoted n! is defined as:
n! = n(n - 1)(n - 2) ... 3.2.1.
Examples:
We define 0! = 1.
4! = (4 x 3
x 2 x 1) = 24.
5! = (5 x 4
x 3 x 2 x 1) = 120.
2. Permutations:
The
different arrangements of a given number of things by taking some or all at a
time, are called permutations.
Examples:
i. All
permutations (or arrangements) made with the letters a, b, c by taking two at a time are (ab, ba, ac, ca, bc, cb).
ii. All
permutations made with the letters a, b, c taking all at a time are:
( abc, acb, bac, bca, cab, cba)
3. Number of Permutations:
Number of
all permutations of n things, taken r at a time, is given by:
nPr = n(n - 1)(n - 2)
... (n - r + 1) = n!/(n - r)!
Examples:
i. 6P2
= (6 x 5) = 30.
ii. 7P3
= (7 x 6 x 5) = 210.
iii. Cor. number of all permutations of n
things, taken all at a time = n!.
4. An Important Result:
If there are
n subjects of which p1 are alike of one kind; p2 are alike of another kind;
p3 are alike of third kind
and so on and pr are alike
of rth kind,
such that (p1
+ p2 + ... pr) = n.
Then, number
of permutations of these n objects is
= n!/ ((p1!).(p2)!.....(pr!))
5. Combinations:
Each of the
different groups or selections which can be formed by taking some or all of a
number of objects is called a combination.
Examples:i. Suppose we want to select two out of three boys
A, B, C. Then, possible selections are AB, BC and CA.
Note: AB and BA represent the same selection.
ii. All the combinations formed by a, b, c taking ab, bc, ca.
iii. The only combination that can be formed of three letters a, b, c taken all at a time is abc.
iv. Various groups of 2 out of four persons A, B, C, D are:1111111
AB, AC, AD, BC, BD, CD.
v. Note that ab ba are two different permutations but they represent the same combination.
Note: AB and BA represent the same selection.
ii. All the combinations formed by a, b, c taking ab, bc, ca.
iii. The only combination that can be formed of three letters a, b, c taken all at a time is abc.
iv. Various groups of 2 out of four persons A, B, C, D are:1111111
AB, AC, AD, BC, BD, CD.
v. Note that ab ba are two different permutations but they represent the same combination.
6. Number
of Combinations:
The number
of all combinations of n things,
taken r at a time is:
nCr
= n!/( (r!)(n - r)!) = (n(n - 1)(n - 2) ... to r factors)/ r! .
Note:
i. nCn = 1 and nC0 = 1.
i. nCn = 1 and nC0 = 1.
ii. nCr
= nC(n - r)
Examples:
i. 11C4 = (11 x 10 x 9 x
8)/ (4 x 3 x 2 x 1) = 330.
ii. 16C13 = 16C(16
- 13) = 16C3 = (16 x 15 x 14)/ 3! = (16 x 15 x 14)/
(3 x 2 x 1) = 560.
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